Zuletzt geändert von akukin am 2025/08/11 15:31

Verstecke letzte Bearbeiter
Kim Fujan 8.1 1 (% class="123" %)
akukin 9.1 2 1. {{formula}} e^x=3 \quad \mid ln( ) {{/formula}}
Kim Fujan 1.1 3 {{formula}} ln(e^x)=ln(3) {{/formula}}
4 {{formula}} x=ln(3) {{/formula}}
Kim Fujan 3.2 5 {{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}}
Kim Fujan 7.1 6
akukin 9.1 7 1. {{formula}} 2e^x-4=8 \quad \mid +4{{/formula}}
8 {{formula}} 2e^x=12 \quad \mid :2{{/formula}}
9 {{formula}} e^x=6 \quad \mid ln( ) {{/formula}}
Kim Fujan 1.1 10 {{formula}} x=ln(6) {{/formula}}
Kim Fujan 4.1 11 {{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}}
Kim Fujan 7.1 12
akukin 9.1 13 1. {{formula}} 2e^{-0.5x}=6 \quad \mid :2 {{/formula}}
14 {{formula}} e^{-0.5x}=3 \quad \mid ln( ) {{/formula}}
15 {{formula}} -0.5x=ln(3) \quad \mid \cdot (-2) {{/formula}}
Kim Fujan 1.3 16 {{formula}} x=-2 \cdot ln(3) {{/formula}}
Kim Fujan 4.1 17 {{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}}
Kim Fujan 7.1 18
akukin 9.1 19 1. {{formula}} e^x=-5 \quad \mid ln( ) {{/formula}}
Kim Fujan 1.3 20 {{formula}}x=ln(-5){{/formula}}
21 keine Lösung!
Kim Fujan 4.1 22 {{formula}}\mathbb{L}= \left\{ \right\} {{/formula}}
Kim Fujan 7.1 23
akukin 9.1 24 1. {{formula}} 4\cdot 5^x=100 \quad \mid:4 {{/formula}}
25 {{formula}} 5^x=25 \quad \mid \text{Exponentenvergleich} {{/formula}}
Kim Fujan 4.2 26 {{formula}} 5^x=5^2 {{/formula}}
Kim Fujan 5.1 27 {{formula}} x=2 {{/formula}}
28 {{formula}}\mathbb{L}= \left\{ 2 \right\} {{/formula}}