Lösung Exponentialgleichungen (Substitution)

Version 1.1 von Kim Fujan am 2025/05/20 10:55

\( -x^{2}+2x-3=0 \)
\( -e^{2x}+2e^x-3=0 \)
\( e^x+2e^{\frac{1}{2}x}-3=0 \)
\( e^x-2-\frac{15}{e^x}}=0 \)
\( 2e^{4x}=e^{2x}+3 \)