Lösung Gleichungen aufstellen II

Zuletzt geändert von Kim Fujan am 2025/05/21 10:12

$c = a^b \: : \qquad 4 = 2^2\:; \qquad 8 = 2^3\:; \qquad 16 = 2^4\:; \qquad 16 = 4^2\:; \qquad 9 = 3^2$

$c = \sqrt[a]{b} \: : \qquad 2 = \sqrt[2]{4}\:; \qquad 2 = \sqrt[3]{8}\:; \qquad 2 = \sqrt[4]{16}\:; \qquad 4 = \sqrt[2]{16}\:; \qquad 3 = \sqrt[2]{9}$

$c = \log_a(b) \: : \qquad 2 = \log_2(4) \:; \qquad 3 = \log_2(8) \:; \qquad 4 = \log_2(16) \:; \qquad 2 = \log_4(16) \:; \qquad 2 = \log_3(9)$

$c = a\cdot b \: : \qquad 4 = 2\cdot 2 \:; \qquad 6 = 2\cdot 3 \:; \qquad 8 = 2\cdot 4 \:; \qquad 10 = 2\cdot 5 \:; \qquad 12 = 2\cdot 6 \:; \qquad 14 = 2\cdot 7 \:; \qquad 16 = 2\cdot 8 \:;$
$6 = 3\cdot 2 \:; \qquad 9 = 3\cdot 3 \:; \qquad 12 = 3\cdot 4 \:; \qquad 15 = 3\cdot 5 \:; \qquad 8 = 4\cdot 2 \:; \qquad 12 = 4\cdot 3 \:; \qquad 16 = 4\cdot 4 \:; \qquad 10 = 5\cdot 2 \:;$
$15 = 5\cdot 3 \:; \qquad 12 = 6\cdot 2 \:; \qquad 14 = 7\cdot 2 \:; \qquad 16 = 8\cdot 2$