Wiki-Quellcode von BPE 1 Einheitsübergreifend
Version 2.1 von Holger Engels am 2025/11/17 09:58
Verstecke letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
 |
1.1 | 1 | {{aufgabe id="Termumformungen" afb="I" quelle="Team Mathebrücke" kompetenzen="" zeit="" cc="by-sa" tags="mathebrücke"}} |
| 2 | Löse die Klammern auf und fasse zusammen („vereinfache“): | ||
| 3 | 1.a) {{formula}}2(4a - 5) - 3(2a - 3) + 4(-3a + 5){{/formula}} | ||
| 4 | 1.b) {{formula}}x - (x + 3) - 4(-x + 1){{/formula}} | ||
| 5 | |||
| 6 | 2.a) {{formula}}6a - 2(7b - (4a + 3b)) + 2((2a - b) - 7a){{/formula}} | ||
| 7 | 2.b) {{formula}}2x + 3(4 - (2x + 1) + 3x){{/formula}} | ||
| 8 | |||
| 9 | Multipliziere aus und vereinfache: | ||
| 10 | 3.a) {{formula}}(3a + b)(a - 5b){{/formula}} | ||
| 11 | 3.b) {{formula}}(4x - 3)(-x + \frac{1}{3}){{/formula}} | ||
| 12 | |||
| 13 | 4.a) {{formula}}(2x + y)^2{{/formula}} | ||
| 14 | 4.b) {{formula}}(x - 3y)^2{{/formula}} | ||
| 15 | 4.c) {{formula}}(x^2 - 2)(x^2 + 2){{/formula}} | ||
| 16 | 4.d) {{formula}}(3 - x)^2 - (x + 1)^2 + 2(x - 1)(x + 1){{/formula}} | ||
| 17 | |||
| 18 | Klammere aus („Faktorisiere“): | ||
| 19 | 5.a) {{formula}}12ax^2 - 8ax{{/formula}} | ||
| 20 | 5.b) {{formula}}3x^2 - 12{{/formula}} | ||
| 21 | 5.c) {{formula}}\frac{3ax^2 - 3a}{9x + 9}{{/formula}} | ||
| 22 | {{/aufgabe}} | ||
| 23 |