Wiki-Quellcode von Lösung Umfang eines Dreiecks
Zeige letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
| 1 | Seitenlängen: | ||
| 2 | {{formula}}\overline{AB} = \sqrt{12^2 + 5^2} = 13{{/formula}} | ||
| 3 | {{formula}}\overline{BC} = \sqrt{9^2 + 9^2} = 9\sqrt{2} \approx 12,73{{/formula}} | ||
| 4 | {{formula}}\overline{CA} = \sqrt{3^2 + 4^2} = 5{{/formula}} | ||
| 5 | |||
| 6 | Umfang: | ||
| 7 | {{formula}}U = \overline{AB} + \overline{BC} + \overline{CA} = 13 + 9\sqrt{2} + 5 = 18 + 9\sqrt{2} \approx 30,73{{/formula}} |