Wiki-Quellcode von Lösung Funktionsterm bestimmen
Version 5.1 von Simone Hochrein am 2025/10/01 12:20
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author | version | line-number | content |
---|---|---|---|
1 | (%class=abc%) | ||
2 | 1. (((Mit den Nullstellen {{formula}}x_1=-3{{/formula}} und {{formula}}x_2=2{{/formula}}: | ||
3 | |||
4 | {{formula}} | ||
5 | \begin{aligned} | ||
6 | &f(x) &= a \cdot (x + 3) (x - 2) ~~~(1) | ||
7 | \end{aligned} | ||
8 | {{/formula}} | ||
9 | |||
10 | Mit {{formula}}P(0|3){{/formula}}: | ||
11 | |||
12 | {{formula}} | ||
13 | \begin{aligned} | ||
14 | &f(0) &= -3 ~~~(2) | ||
15 | \end{aligned} | ||
16 | {{/formula}} | ||
17 | |||
18 | {{formula}}(2){{/formula}} in {{formula}}(1){{/formula}}: | ||
19 | |||
20 | {{formula}} | ||
21 | \begin{aligned} | ||
22 | a \cdot (0 + 3) (0 - 2) &= -3\\ | ||
23 | -6a &= -3 \\ | ||
24 | ~a &= 0,5 \\ | ||
25 | \end{aligned} | ||
26 | {{/formula}} | ||
27 | |||
28 | {{formula}} | ||
29 | \Rightarrow f(x)=0,5\cdot (x+3)(x-2) | ||
30 | {{/formula}} | ||
31 | ))) |