Lösung Basiswechel

a) \((\frac{1}{4})^x=(2^{-x})^x=2^{-2x}\)
b) \((\frac{3}{18})^x=(\frac{1}{6})^=6^{-x}\)
c) \(5^{2x+1}=5\cdot (5^2)^x=5\cdot 25^x\)
d) \((\frac{16}{54})^{2x}=(\frac{8}{27})^{2x}=(\frac{2}{3})^{3\cdot 2x}=(-\frac{2}{3})^{-6x}\)