Wiki-Quellcode von Lösung Basiswechel

Zuletzt geändert von Holger Engels am 2025/03/10 20:46

author	version	line-number	content
		1	(% class="abc" %)
		2	1. ((({{formula}}f(x)=(\frac{1}{4})^x{{/formula}}, neue Basis {{formula}}b=2{{/formula}}
		3
		4	{{formula}}\frac{1}{4} = 2^{-2} \Rightarrow f(x)=2^{-2x}{{/formula}}
		5	)))
		6	1. ((({{formula}}f(x)=9^x{{/formula}}, neue Basis {{formula}}b=\frac{1}{3}{{/formula}}
		7
		8	{{formula}}9 = (\frac{1}{3})^{-2} \Rightarrow f(x)=(\frac{1}{3})^{-2x}{{/formula}}
		9	)))
		10	1. ((({{formula}}f(x)=5^{2x+1}{{/formula}}, neue Basis {{formula}}b=25{{/formula}}
		11
		12	{{formula}}5 = 25^{\frac{1}{2}} \Rightarrow f(x)=25^{\frac{1}{2}\cdot(2x+1)}=25^{x+\frac{1}{2}}{{/formula}}
		13	)))