Wiki-Quellcode von Lösung Exponentialgleichungen rückwärts lösen
Version 1.1 von Martina Wagner am 2025/05/20 14:10
Zeige letzte Bearbeiter
author | version | line-number | content |
---|---|---|---|
1 | |||
2 | 1. ((({{{ }}} | ||
3 | |||
4 | {{formula}} | ||
5 | \begin{align*} | ||
6 | 2 e^x-2 &= 0\\ | ||
7 | 2 e^x &=2\quad \left|:2\\ | ||
8 | e^x &=1 \\ | ||
9 | x &= 0 | ||
10 | \end{align*} | ||
11 | {{/formula}} | ||
12 | ))) | ||
13 | 1. ((({{{ }}} | ||
14 | |||
15 | {{formula}} | ||
16 | \begin{align*} | ||
17 | e^{2x}-\square e^x &= 0 \\ | ||
18 | e^x(\square-\square) &= 0 \left|\left| \text{ SVNP } | ||
19 | \end{align*} | ||
20 | {{/formula}} | ||
21 | |||
22 | {{formula}}\ e^x \neq 0 ~und~ e^x-\square = 0{{/formula}} | ||
23 | |||
24 | {{formula}} x =\square {{/formula}} | ||
25 | ))) | ||
26 | 1. ((({{{ }}} | ||
27 | |||
28 | {{formula}} | ||
29 | \begin{align*} | ||
30 | e^{2x}-\square e^x+\square &= 0 \quad \left|\left|\text{ Subst.: } e^x:=\square\\ | ||
31 | z^2-\square z + \square &= 0 \quad \left|\left|\text{ Mitternachtsformel/abc-Formel } & | ||
32 | \end{align*} | ||
33 | {{/formula}} | ||
34 | |||
35 | {{formula}} | ||
36 | \begin{align*} | ||
37 | \Rightarrow z_{1,2}&=\frac{\square\pm\sqrt{\square^2-4\cdot\square\cdot\square}}{2\cdot\square}\\ | ||
38 | z_{1,2}&=\frac{\square+\square}{\square} | ||
39 | \end{align*} | ||
40 | {{/formula}} | ||
41 | |||
42 | {{formula}} | ||
43 | \begin{align*} | ||
44 | &\text{Resubst.: } z:= e^x\\ | ||
45 | &e^x=\square \Rightarrow x \approx 0,693147...\\ | ||
46 | \end{align*} | ||
47 | {{/formula}} | ||
48 | ))) | ||
49 | {{/aufgabe}} |