Wiki-Quellcode von Lösung Vektoraddition
Version 3.1 von Daniel Stocker am 2023/11/30 15:42
Zeige letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
| 1 | {{formula}}\begin{align*}\overrightarrow{AB} &= \left(\begin{array}{c} 5-3 \\ 2-1 \\ 4-5\end{array}\right) &= \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right) \\ | ||
| 2 | \overrightarrow{CA} &= \left(\begin{array}{c} 3-8 \\ 1-7 \\ 5-1 \end{array}\right) &= \left(\begin{array}{c} -5 \\ -6 \\ -4 \end{array}\right) \\ | ||
| 3 | \overrightarrow{BC} &= \left(\begin{array}{c} 8-5 \\ 7-2 \\ 1-4 \end{array}\right) &= \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) \\ | ||
| 4 | \overrightarrow{DA} &= \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right) | ||
| 5 | \end{align*} | ||
| 6 | {{/formula}} | ||
| 7 | |||
| 8 | {{formula}} | ||
| 9 | \overrightarrow{AB}-\overrightarrow{CA}+\overrightarrow{BC}-\overrightarrow{DA}&=\overrightarrow{o} | ||
| 10 | {{/formula}} | ||
| 11 | |||
| 12 | {{formula}} | ||
| 13 | \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right)-\left(\begin{array}{c} -5 \\ -6 \\ -4 \end{array}\right) + \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) - \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right) &= \left(\begin{array}{c} 0 \\ 0 \\ 0 \end{array}\right) | ||
| 14 | {{/formula}} | ||
| 15 | |||
| 16 | {{formula}} | ||
| 17 | \text{I:} | ||
| 18 | {{/formula}} |