Lösung Element von
Version 3.1 von Anna Kukin am 2024/04/01 18:43
| \(\mathbb{N}\) | \(\mathbb{N}_0\) | \(\mathbb{Z}^-\) | \(\mathbb{Z}_+\) | \(\mathbb{Z}\) | \(\mathbb{Q}^-\) | \(\mathbb{Q}^+\) | \(\mathbb{Q}\) | \(\mathbb{R}^-\) | \(\mathbb{R}^+\) | \(\mathbb{R}\) | |
|---|---|---|---|---|---|---|---|---|---|---|---|
| \(\frac{3}{4}\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\in\) | \(\in\) | \(\notin\) | \(\in\) | \(\in\) |
| \(\frac{-4}{5}\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\in\) | \(\notin\) | \(\in\) | \(\in\) | \(\notin\) | \(\in\) |
| \(-\frac{6}{5}\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\notin\) | \(\in\) | \(\notin\) | \(\in\) | \(\in\) | \(\notin\) | \(\in\) |
| \(\frac{10}{2}=5|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}} |= {{formula}}4{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}} |= {{formula}}0{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}-6{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt[4]{16}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt{4}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt{5}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}(-3)^5{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}3^{-1}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}(-2)^{-2}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}tan 45^{o}{{/formula}}|=|=|=|=|=|=|=|=|=|=|=\) |