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Lösung Element von

Version 3.1 von akukin am 2024/04/01 18:43
\mathbb{N}\mathbb{N}_0\mathbb{Z}^-\mathbb{Z}_+\mathbb{Z}\mathbb{Q}^-\mathbb{Q}^+\mathbb{Q}\mathbb{R}^-\mathbb{R}^+\mathbb{R}
 \frac{3}{4}\notin\notin\notin\notin\notin\notin\in\in\notin\in\in
 \frac{-4}{5}\notin\notin\notin\notin\notin\in\notin\in\in\notin\in
 -\frac{6}{5}\notin\notin\notin\notin\notin\in\notin\in\in\notin\in
 \frac{10}{2}=5|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}} |= {{formula}}4{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\notin{{/formula}}|={{formula}}\in{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\notin{{/formula}}|{{formula}}\in{{/formula}}|={{formula}}\in{{/formula}} |= {{formula}}0{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}-6{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt[4]{16}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt{4}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}\sqrt{5}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}(-3)^5{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}3^{-1}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}(-2)^{-2}{{/formula}}|=|=|=|=|=|=|=|=|=|=|= |= {{formula}}tan 45^{o}{{/formula}}|=|=|=|=|=|=|=|=|=|=|=