Zum Inhalt springen

Lösung Vereinfachen

Version 9.1 von Holger Engels am 2024/10/15 12:14
  1. \(\left(2^{3}\right)^{2}=2^{3\cdot2}=2^{6}=64\)
  2. \(\left(6b^6\right):\left(3b^3\right)=\frac{6b^6}{3b^3}=\frac{2 \cdot 3}{3}\cdot b^{6-3}=2 \cdot b^{3}\)
  3. \(2^x\cdot2^{3-x}=2^{x+(3-x)}=2^3=8\)
  4. \(\frac{1}{8}\cdot2^{3+x}=2^x\)
  5. \(\frac{x^{2u}\cdot x^{a-u}}{x^u}=\frac{x^{2u}\cdot x^{a}\cdot x^{-u}}{x^u}=\frac{x^{2u}\cdot x^{a}}{x^u\cdot x^{+u}}=\frac{x^{2u}\cdot x^{a}}{x^{2u}}=x^{a}\)