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Lösung Vereinfachen

Version 9.1 von Holger Engels am 2024/10/15 14:14
  1. \left(2^{3}\right)^{2}=2^{3\cdot2}=2^{6}=64
  2. \left(6b^6\right):\left(3b^3\right)=\frac{6b^6}{3b^3}=\frac{2 \cdot 3}{3}\cdot b^{6-3}=2 \cdot b^{3}
  3. 2^x\cdot2^{3-x}=2^{x+(3-x)}=2^3=8
  4. \frac{1}{8}\cdot2^{3+x}=2^x
  5. \frac{x^{2u}\cdot x^{a-u}}{x^u}=\frac{x^{2u}\cdot x^{a}\cdot x^{-u}}{x^u}=\frac{x^{2u}\cdot x^{a}}{x^u\cdot x^{+u}}=\frac{x^{2u}\cdot x^{a}}{x^{2u}}=x^{a}