Änderungen von Dokument Lösung Exponentialgleichungen (Logarithmieren)

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...	...	@@ -1,14 +1,24 @@
1	1	(% class="abc" %)
2		-1. {{formula}} e^x=3 \square\left| ln( ) {{/formula}}
	2	+1. {{formula}} e^x=3 \quad \left| ln( ) {{/formula}}
3	3	{{formula}} ln(e^x)=ln(3) {{/formula}}
4	4	{{formula}} x=ln(3) {{/formula}}
5		-1. {{formula}} 2e^x-4=8 \square\ \left|+4{{/formula}}
6		-{{formula}} 2e^x=12 \square \left|:2{{/formula}}
7		-{{formula}} e^x=6 \square\ \left| ln( ) {{/formula}}
	5	+{{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}}
	6	+1. {{formula}} 2e^x-4=8 \quad \left|+4{{/formula}}
	7	+{{formula}} 2e^x=12 \quad \left|:2{{/formula}}
	8	+{{formula}} e^x=6 \quad \left| ln( ) {{/formula}}
8	8	{{formula}} x=ln(6) {{/formula}}
9		-1. {{formula}} 2e^{-0.5x}=6{{/formula}}
10		-
11		-1. {{formula}} e^x=-5 {{/formula}}
12		-
13		-1. {{formula}} 4\cdot 5^x=100 {{/formula}}
14		-
	10	+{{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}}
	11	+1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}}
	12	+{{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}}
	13	+{{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}}
	14	+{{formula}} x=-2 \cdot ln(3) {{/formula}}
	15	+{{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}}
	16	+1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}}
	17	+{{formula}}x=ln(-5){{/formula}}
	18	+keine Lösung!
	19	+{{formula}}\mathbb{L}= \left\{ \right\} {{/formula}}
	20	+1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}}
	21	+{{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}}
	22	+{{formula}} 5^x=5^2 {{/formula}}
	23	+{{formula}} x=2 {{/formula}}
	24	+{{formula}}\mathbb{L}= \left\{ 2 \right\} {{/formula}}