Änderungen von Dokument Lösung Exponentialgleichungen (Logarithmieren)

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...	...	@@ -2,20 +2,23 @@
2	2	1. {{formula}} e^x=3 \quad \left| ln( ) {{/formula}}
3	3	{{formula}} ln(e^x)=ln(3) {{/formula}}
4	4	{{formula}} x=ln(3) {{/formula}}
5		-
	5	+{{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}}
6	6	1. {{formula}} 2e^x-4=8 \quad \left|+4{{/formula}}
7	7	{{formula}} 2e^x=12 \quad \left|:2{{/formula}}
8	8	{{formula}} e^x=6 \quad \left| ln( ) {{/formula}}
9	9	{{formula}} x=ln(6) {{/formula}}
10		-
	10	+{{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}}
11	11	1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}}
12	12	{{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}}
13	13	{{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}}
14	14	{{formula}} x=-2 \cdot ln(3) {{/formula}}
15		-
	15	+{{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}}
16	16	1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}}
17	17	{{formula}}x=ln(-5){{/formula}}
18	18	keine Lösung!
19		-
20		-1. {{formula}} 4\cdot 5^x=100 {{/formula}}
21		-
	19	+{{formula}}\mathbb{L}= \left\{ \right\} {{/formula}}
	20	+1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}}
	21	+{{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}}
	22	+{{formula}} 5^x=5^2 {{/formula}}
	23	+{{formula}} x=2 {{/formula}}
	24	+{{formula}}\mathbb{L}= \left\{ 2 \right\} {{/formula}}