Änderungen von Dokument Lösung Exponentialgleichungen (Logarithmieren)
Zuletzt geändert von Kim Fujan am 2025/05/20 11:11
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... ... @@ -2,7 +2,7 @@ 2 2 1. {{formula}} e^x=3 \quad \left| ln( ) {{/formula}} 3 3 {{formula}} ln(e^x)=ln(3) {{/formula}} 4 4 {{formula}} x=ln(3) {{/formula}} 5 -{{formula}}\mathbb{L}=\left{ ln(3) \right} {{/formula}} 5 +{{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}} 6 6 7 7 8 8 1. {{formula}} 2e^x-4=8 \quad \left|+4{{/formula}} ... ... @@ -9,15 +9,20 @@ 9 9 {{formula}} 2e^x=12 \quad \left|:2{{/formula}} 10 10 {{formula}} e^x=6 \quad \left| ln( ) {{/formula}} 11 11 {{formula}} x=ln(6) {{/formula}} 12 +{{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}} 12 12 13 13 1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}} 14 14 {{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}} 15 15 {{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}} 16 16 {{formula}} x=-2 \cdot ln(3) {{/formula}} 18 +{{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}} 17 17 18 18 1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}} 19 19 {{formula}}x=ln(-5){{/formula}} 20 20 keine Lösung! 23 +{{formula}}\mathbb{L}= \left\{ \right\} {{/formula}} 21 21 22 -1. {{formula}} 4\cdot 5^x=100 {{/formula}} 23 - 25 +1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}} 26 +{{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}} 27 +{{formula}} 5^x=5^2 {{/formula}} 28 +{{formula}} x=5 {{/formula}}