Änderungen von Dokument Lösung Exponentialgleichungen (Logarithmieren)

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...	...	@@ -9,15 +9,20 @@
9	9	{{formula}} 2e^x=12 \quad \left|:2{{/formula}}
10	10	{{formula}} e^x=6 \quad \left| ln( ) {{/formula}}
11	11	{{formula}} x=ln(6) {{/formula}}
	12	+{{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}}
12	12
13	13	1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}}
14	14	{{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}}
15	15	{{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}}
16	16	{{formula}} x=-2 \cdot ln(3) {{/formula}}
	18	+{{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}}
17	17
18	18	1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}}
19	19	{{formula}}x=ln(-5){{/formula}}
20	20	keine Lösung!
	23	+{{formula}}\mathbb{L}= \left\{ \right\} {{/formula}}
21	21
22		-1. {{formula}} 4\cdot 5^x=100 {{/formula}}
23		-
	25	+1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}}
	26	+{{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}}
	27	+{{formula}} 5^x=5^2 {{/formula}}
	28	+{{formula}} x=5 {{/formula}}