Version 5.1 von Kim Fujan am 2025/05/20 13:10

Verstecke letzte Bearbeiter
Kim Fujan 2.1 1 (% class="abc" %)
2 1. {{formula}} x^{2}+2x-3=0 {{/formula}}
Kim Fujan 4.1 3
Kim Fujan 2.1 4 Lösung mit abc-Formel:
Kim Fujan 3.1 5 {{formula}}x_{1,2}=\frac{2\pm \sqrt{4+12}}{2}=\frac{2\pm 4}{2}{{/formula}}
6 {{formula}} x_{1}=3 \quad ; \quad x_{2}=-1 {{/formula}}
Kim Fujan 4.1 7
Kim Fujan 2.1 8 1. {{formula}} e^{2x}+2e^x-3=0 {{/formula}}
9
Kim Fujan 4.1 10 Substitution: {{formula}} e^x=u {{/formula}}
11 {{formula}} u^{2}+2u-3=0 {{/formula}}
12
13 Lösung mit abc-Formel:
14 {{formula}}u_{1,2}=\frac{2\pm \sqrt{4+12}}{2}=\frac{2\pm 4}{2}{{/formula}}
15 {{formula}} u_{1}=3 \quad ; \quad u_{2}=-1 {{/formula}}
Kim Fujan 5.1 16
Kim Fujan 4.1 17 Resubstitution:
18 {{formula}} e^x=3 \quad \Longleftrightarrow \quad x=ln(3) {{/formula}}
19 {{formula}} e^x=-1 \quad \Longleftrightarrow \quad {{/formula}} keine weitere Lösung!
20
21
Kim Fujan 1.1 22 1. {{formula}} e^x+2e^{\frac{1}{2}x}-3=0 {{/formula}}
Kim Fujan 2.1 23
Kim Fujan 5.1 24 Substitution: {{formula}} e^{\frac{1}{2}x}=u {{/formula}}
25 {{formula}} u^{2}+2u-3=0 {{/formula}}
26
27 Lösung mit abc-Formel:
28 {{formula}}u_{1,2}=\frac{2\pm \sqrt{4+12}}{2}=\frac{2\pm 4}{2}{{/formula}}
29 {{formula}} u_{1}=3 \quad ; \quad u_{2}=-1 {{/formula}}
30
31 Resubstitution:
32 {{formula}} e^{\frac{1}{2}x}=3 \quad \Longleftrightarrow \quad x=2 \cdot ln(3) {{/formula}}
33 {{formula}} e^{\frac{1}{2}x}=-1 \quad \Longleftrightarrow \quad {{/formula}} keine weitere Lösung!
34
Kim Fujan 2.1 35 1. {{formula}} e^x-2-\frac{15}{e^x}}=0 {{/formula}}
36
Kim Fujan 1.1 37 1. {{formula}} 2e^{4x}=e^{2x}+3 {{/formula}}