Wiki-Quellcode von Lösung Tangente in einem Kurvenpunkt II
Version 6.3 von Dirk Tebbe am 2025/10/13 14:14
Zeige letzte Bearbeiter
author | version | line-number | content |
---|---|---|---|
1 | 1. | ||
2 | [[image:Exponentialfunktion.svg||width="450" style="display:block;margin-left:auto;margin-right:auto"]] | ||
3 | 1. | ||
4 | {{formula}}f\left(x\right)=0{{/formula}} | ||
5 | {{formula}}4-\frac{1}{2} e^x=0{{/formula}} | ||
6 | {{formula}}4=\frac{1}{2} e^x{{/formula}} | ||
7 | {{formula}}8=e^x{{/formula}} | ||
8 | {{formula}}ln(8)=x{{/formula}} | ||
9 | |||
10 | {{formula}}f´\left(x\right)=-\frac{1}{2} e^x{{/formula}} | ||
11 | {{formula}}f´\left(ln(8)\right)=-\frac{1}{2} e^{ln(8)}=-\frac{1}{2}\cdot 8=-4{{/formula}} | ||
12 | |||
13 | Einsetzen von {{formula}}m=-4{{/formula}} in {{formula}}y=mx+c{{/formula}}: | ||
14 | {{formula}}y= -4x+c{{/formula}} | ||
15 | und {{formula}}N(ln(8)|0){{/formula}} | ||
16 | {{formula}} 0= -4 \cdot ln(8)+c{{/formula}} | ||
17 | {{formula}} c = 4 \cdot ln(8){{/formula}} | ||
18 | |||
19 | {{formula}}y=-4\cdot x+ 4 \cdot ln(8){{/formula}} | ||
20 | |||
21 | {{formula}}4-\frac{1}{2} e^x=4{{/formula}} | ||
22 | {{formula}}-\frac{1}{2} e^x=0{{/formula}} | ||
23 | {{formula}} e^x=0{{/formula}} | ||
24 | Diese Gleichung hat keine Lösung, da {{formula}} e^x\neq 0{{/formula}} | ||
25 | |||
26 | {{formula}}f´\left(x\right)=-\frac{1}{2} e^x< 0{{/formula}} für alle x. |