Wiki-Quellcode von Lösung Exponentialgleichungen rückwärts lösen
Version 1.1 von Martina Wagner am 2025/05/20 12:10
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| author | version | line-number | content |
|---|---|---|---|
| 1 | |||
| 2 | 1. ((({{{ }}} | ||
| 3 | |||
| 4 | {{formula}} | ||
| 5 | \begin{align*} | ||
| 6 | 2 e^x-2 &= 0\\ | ||
| 7 | 2 e^x &=2\quad \left|:2\\ | ||
| 8 | e^x &=1 \\ | ||
| 9 | x &= 0 | ||
| 10 | \end{align*} | ||
| 11 | {{/formula}} | ||
| 12 | ))) | ||
| 13 | 1. ((({{{ }}} | ||
| 14 | |||
| 15 | {{formula}} | ||
| 16 | \begin{align*} | ||
| 17 | e^{2x}-\square e^x &= 0 \\ | ||
| 18 | e^x(\square-\square) &= 0 \left|\left| \text{ SVNP } | ||
| 19 | \end{align*} | ||
| 20 | {{/formula}} | ||
| 21 | |||
| 22 | {{formula}}\ e^x \neq 0 ~und~ e^x-\square = 0{{/formula}} | ||
| 23 | |||
| 24 | {{formula}} x =\square {{/formula}} | ||
| 25 | ))) | ||
| 26 | 1. ((({{{ }}} | ||
| 27 | |||
| 28 | {{formula}} | ||
| 29 | \begin{align*} | ||
| 30 | e^{2x}-\square e^x+\square &= 0 \quad \left|\left|\text{ Subst.: } e^x:=\square\\ | ||
| 31 | z^2-\square z + \square &= 0 \quad \left|\left|\text{ Mitternachtsformel/abc-Formel } & | ||
| 32 | \end{align*} | ||
| 33 | {{/formula}} | ||
| 34 | |||
| 35 | {{formula}} | ||
| 36 | \begin{align*} | ||
| 37 | \Rightarrow z_{1,2}&=\frac{\square\pm\sqrt{\square^2-4\cdot\square\cdot\square}}{2\cdot\square}\\ | ||
| 38 | z_{1,2}&=\frac{\square+\square}{\square} | ||
| 39 | \end{align*} | ||
| 40 | {{/formula}} | ||
| 41 | |||
| 42 | {{formula}} | ||
| 43 | \begin{align*} | ||
| 44 | &\text{Resubst.: } z:= e^x\\ | ||
| 45 | &e^x=\square \Rightarrow x \approx 0,693147...\\ | ||
| 46 | \end{align*} | ||
| 47 | {{/formula}} | ||
| 48 | ))) | ||
| 49 | {{/aufgabe}} |