Wiki-Quellcode von Lösung Orthogonalen Vektor finden
Zuletzt geändert von Holger Engels am 2024/10/19 20:10
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| author | version | line-number | content |
|---|---|---|---|
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4.1 | 1 | {{formula}}\vec u \cdot \vec v = \left(\begin{array}{c} 4 \\ 5 \\ 2\end{array}\right) \cdot \left(\begin{array}{c} \frac{2}{3} \\ a \\ -1\end{array}\right) = 4 \cdot \frac{2}{3} + 5 \cdot a + 2 \cdot (-1) \overset{!}{=} 0 {{/formula}} |
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2.1 | 2 | |
| 3 | {{formula}} | ||
| 4 | \begin{align*} | ||
| 5 | 4 \cdot \frac{2}{3} + 5 \cdot a + 2 \cdot (-1) &= 0 \\ | ||
| 6 | \frac{8}{3} + 5a -2 &= 0 \\ | ||
| |
3.1 | 7 | \frac{2}{3} + 5a &= 0 \\ |
| 8 | 5a &= -\frac{2}{3} \\ | ||
| 9 | a &= -\frac{2}{15} | ||
| |
2.1 | 10 | \end{align*} |
| 11 | {{/formula}} |