Lösung Potenzgleichungsmauer

Zuletzt geändert von Bastian Knöpfle am 2025/10/01 08:19

\(x=2\) \(x=\color{red}{-2}\)
\(x^5=\color{red}{32}\) \(x^\color{red}{4}=16\) \(x^\color{red}{3}+8=0\)
\(x=\color{red}{3}\) \(x=-3\)
\(x^\color{red}{3}=27\) \(x^{-2}=\color{red}{\frac{1}{9}}\) \(x^\color{red}{-1}=-\frac{1}{3}\)

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	\(x=2\)		\(x=\color{red}{-2}\)
\(x^5=\color{red}{32}\)		\(x^\color{red}{4}=16\)		\(x^\color{red}{3}+8=0\)

	\(x=\color{red}{3}\)		\(x=-3\)
\(x^\color{red}{3}=27\)		\(x^{-2}=\color{red}{\frac{1}{9}}\)		\(x^\color{red}{-1}=-\frac{1}{3}\)

unfertig	fertig
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