Wiki-Quellcode von Lösung Oberflächenvergleich
Version 12.1 von Bastian Knöpfle am 2026/02/03 10:59
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| author | version | line-number | content |
|---|---|---|---|
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1.1 | 1 | Würfel: |
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4.1 | 2 | {{formula}}V=a^3=1000 \mathrm{cm}^3 \Rightarrow a=10\mathrm{cm}{{/formula}} |
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12.1 | 3 | |
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5.1 | 4 | {{formula}}O=6 \cdot a^2=600\mathrm{cm}^2{{/formula}} |
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12.1 | 5 | |
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1.1 | 6 | Kugel: |
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11.1 | 7 | {{formula}}V=\frac{4}{3} \cdot \pi r^3 =1000 \mathrm{cm}^3 \Rightarrow r=\sqrt[3]{\frac{3V}{4 \pi}} =\sqrt[3]{\frac{3 \cdot 1000}{4 \pi}} =6,2 \mathrm{cm} {{/formula}} |
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12.1 | 8 | |
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7.1 | 9 | {{formula}}O=4 \pi \cdot r^2 = 4 \pi (6,2 \mathrm{cm})^2 =483 \mathrm{cm}^2 {{/formula}} |
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12.1 | 10 | |
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5.1 | 11 | Zyliner: |
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8.1 | 12 | {{formula}}V=\pi \cdot r^2 \cdot h \quad \text{mit} \quad h=2r {{/formula}} |
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11.1 | 13 | {{formula}} V=2 \pi r^3{{/formula}} |
| 14 | {{formula}} r=\sqrt[3]{\frac{V}{2 \pi}}=\sqrt[3]{\frac{1000}{2 \pi}}=5,42\mathrm{cm}{{/formula}} | ||
| 15 | |||
| 16 | {{formula}} O=2 \pi \cdot r^2+2\pi \cdot r \cdot h \quad \text{mit} \quad h=2r {{/formula}} | ||
| 17 | {{formula}} O=2 \pi \cdot r^2+2\pi \cdot r \cdot 2r {{/formula}} | ||
| 18 | {{formula}} O=2 \pi \cdot r^2+4\pi \cdot r^2 {{/formula}} | ||
| 19 | {{formula}} O=2 \pi \cdot (5,42\mathrm{cm})^2+4\pi \cdot (5,42\mathrm{cm})^2=553,6 \mathrm{cm}^2 {{/formula}} |