Wiki-Quellcode von Lösung Zuordnungsaufgabe Ausklammern/Faktorisieren
Zuletzt geändert von akukin am 2025/07/15 12:24
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| author | version | line-number | content |
|---|---|---|---|
| 1 | (%class="border%) | ||
| 2 | |Term |Auswahlmöglichkeiten |Lösungsfeld | ||
| 3 | |1) {{formula}}3x^2 - 2x{{/formula}} | a) {{formula}}x(3x-2){{/formula}} \\ b) {{formula}}3x{{/formula}} \\ c) {{formula}}3x(x-2){{/formula}} |a) | ||
| 4 | |2) {{formula}}2x^2 - 8{{/formula}} | a) {{formula}}2(x+2)(x-2){{/formula}} \\ b) {{formula}}2(x-2)^2{{/formula}} \\ c) {{formula}}2x(x-2){{/formula}} |a) | ||
| 5 | |3) {{formula}}\frac{x^2 - 9}{x + 3}{{/formula}} | a) {{formula}}x - 3{{/formula}} \\ b) {{formula}}x{{/formula}} \\ c) {{formula}}x + 3{{/formula}} |a) | ||
| 6 | |4) {{formula}}x^3 + 2x^2{{/formula}} | a) {{formula}}2x^5{{/formula}} \\ b) {{formula}}2x^6{{/formula}} \\ c) {{formula}}x^2(x+2){{/formula}} |c) | ||
| 7 | |5) {{formula}}5x^2 - 10x + 5{{/formula}} | a) {{formula}}5(x+1)^2{{/formula}} \\ b) {{formula}}5(x-1)^2{{/formula}} \\ c) {{formula}}5(x-1)(x+1){{/formula}} |b) |