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Lösung Element von

Version 6.1 von akukin am 2024/04/01 16:58
\(\mathbb{N}\)\(\mathbb{N}_0\)\(\mathbb{Z}^-\)\(\mathbb{Z}_+\)\(\mathbb{Z}\)\(\mathbb{Q}^-\)\(\mathbb{Q}^+\)\(\mathbb{Q}\)\(\mathbb{R}^-\)\(\mathbb{R}^+\)\(\mathbb{R}\)
 \(\frac{3}{4}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(\frac{-4}{5}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)
 \(-\frac{6}{5}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)
 \(\frac{10}{2}=5\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(4\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(0\)\(\notin\)\(\in\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\notin\)\(\in\)
 \(-6\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)
 \(\sqrt[4]{16}=2\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(\sqrt{4}=2\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(\sqrt{5}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\in\)
 \((-3)^5=-243\)\(\notin\)\(\notin\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)
 \(3^{-1}=\frac{1}{3}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \((-2)^{-2}=\frac{1}{4}\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)
 \(tan 45^{o}=1\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)\(\notin\)\(\in\)\(\in\)