Wiki-Quellcode von Lösung Vereinfachen
Verstecke letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
 |
4.1 | 1 | 1.) {{formula}}\frac{1}{4}\cdot2^{a+2}=\frac{1}{2^2}\cdot2^{a}\cdot2^{2}=2^{a}{{/formula}} |
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7.1 | 2 | 2.) {{formula}}\frac{x^{2u}\cdot x^{a-u}}{x^u}=\frac{x^{2u}\cdot x^{a}\cdot x^{-u}}{x^u}=\frac{x^{2u}\cdot x^{a}}{x^u\cdot x^{+u}}=\frac{x^{2u}\cdot x^{a}}{x^{2u}}{{/formula}} |