Version 4.2 von Kim Fujan am 2025/05/20 11:06

Verstecke letzte Bearbeiter
Kim Fujan 1.1 1 (% class="abc" %)
Kim Fujan 1.2 2 1. {{formula}} e^x=3 \quad \left| ln( ) {{/formula}}
Kim Fujan 1.1 3 {{formula}} ln(e^x)=ln(3) {{/formula}}
4 {{formula}} x=ln(3) {{/formula}}
Kim Fujan 3.2 5 {{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}}
Kim Fujan 1.2 6
Kim Fujan 2.1 7
Kim Fujan 1.2 8 1. {{formula}} 2e^x-4=8 \quad \left|+4{{/formula}}
9 {{formula}} 2e^x=12 \quad \left|:2{{/formula}}
10 {{formula}} e^x=6 \quad \left| ln( ) {{/formula}}
Kim Fujan 1.1 11 {{formula}} x=ln(6) {{/formula}}
Kim Fujan 4.1 12 {{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}}
Kim Fujan 1.1 13
Kim Fujan 1.2 14 1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}}
15 {{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}}
16 {{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}}
Kim Fujan 1.3 17 {{formula}} x=-2 \cdot ln(3) {{/formula}}
Kim Fujan 4.1 18 {{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}}
Kim Fujan 1.2 19
Kim Fujan 1.3 20 1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}}
21 {{formula}}x=ln(-5){{/formula}}
22 keine Lösung!
Kim Fujan 4.1 23 {{formula}}\mathbb{L}= \left\{ \right\} {{/formula}}
Kim Fujan 1.1 24
Kim Fujan 4.2 25 1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}}
26 {{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}}
27 {{formula}} 5^x=5^2 {{/formula}}
28 {{formula}} x=5 {{/formula}}