Änderungen von Dokument Lösung In Summe Null
Zuletzt geändert von akukin am 2025/08/14 15:55
Von Version 3.1
bearbeitet von Daniel Stocker
am 2023/11/30 14:42
am 2023/11/30 14:42
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... ... @@ -1,1 +1,1 @@ 1 -Lösung Vektoraddition1 +Lösung In Summe Null - Dokument-Autor
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... ... @@ -1,1 +1,1 @@ 1 -XWiki. daniel22171 +XWiki.akukin - Inhalt
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... ... @@ -1,18 +1,32 @@ 1 -{{formula}}\begin{align*}\overrightarrow{AB} &= \left(\begin{array}{c} 5-3 \\ 2-1 \\ 4-5\end{array}\right) &= \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right) \\ 2 -\overrightarrow{CA} &= \left(\begin{array}{c} 3-8 \\ 1-7 \\ 5-1 \end{array}\right) &= \left(\begin{array}{c} -5 \\ -6 \\ -4 \end{array}\right) \\ 3 -\overrightarrow{BC} &= \left(\begin{array}{c} 8-5 \\ 7-2 \\ 1-4 \end{array}\right) &= \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) \\ 1 +{{formula}} 2 +\begin{align*}\overrightarrow{AB} &= \left(\begin{array}{c} 5-3 \\ 2-1 \\ 4-5\end{array}\right) = \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right) \\ 3 +\overrightarrow{CA} &= \left(\begin{array}{c} 3-8 \\ 1-7 \\ 5-1 \end{array}\right) = \left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) \\ 4 +\overrightarrow{BC} &= \left(\begin{array}{c} 8-5 \\ 7-2 \\ 1-4 \end{array}\right) = \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) \\ 4 4 \overrightarrow{DA} &= \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right) 5 5 \end{align*} 6 6 {{/formula}} 7 7 8 -{{formula}} 9 -\overrightarrow{AB}-\overrightarrow{CA}+\overrightarrow{BC}-\overrightarrow{DA}&=\overrightarrow{o} 10 -{{/formula}} 9 +{{formula}}\overrightarrow{AB}-\overrightarrow{CA}+\overrightarrow{BC}-\overrightarrow{DA}=\overrightarrow{o}{{/formula}} 11 11 11 +{{formula}}\left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right)-\left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) + \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) - \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right)= \left(\begin{array}{c} 0 \\ 0 \\ 0 \end{array}\right){{/formula}} 12 + 12 12 {{formula}} 13 -\left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right)-\left(\begin{array}{c} -5 \\ -6 \\ -4 \end{array}\right) + \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) - \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right) &= \left(\begin{array}{c} 0 \\ 0 \\ 0 \end{array}\right) 14 +\begin{align*} 15 +&\text{I: } &2-(-5)+3-(3-d_1) &= 0 \\ 16 +& &10-3+d_1 &= 0\\ 17 +& &d_1 &= -7 \\ 18 +&\text{II: } &1-(-6)+5-(1-d_2) &= 0 \\ 19 +& &12-1+d_2 &= 0\\ 20 +& &d_2 &= -11 \\ 21 +&\text{III: } &-1-4+(-3)-(5-d_3) &= 0 \\ 22 +& &-8-5+d_3 &= 0\\ 23 +& &d_3 &= 13 24 +\end{align*} 14 14 {{/formula}} 15 15 16 16 {{formula}} 17 -\t ext{I:}28 +\Rightarrow D(-7|-11|13) 18 18 {{/formula}} 30 + 31 + 32 +