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Änderungen von Dokument Lösung In Summe Null

Zuletzt geändert von akukin am 2025/08/14 15:55
Von Version 5.1
bearbeitet von akukin
am 2025/08/14 15:55
Änderungskommentar: Es gibt keinen Kommentar für diese Version
Auf Version 4.1
bearbeitet von Daniel Stocker
am 2023/11/30 14:43
Änderungskommentar: Zurück zur Version 2.1

Zusammenfassung

Details

Seiteneigenschaften
Titel
... ... @@ -1,1 +1,1 @@
1 -Lösung In Summe Null
1 +Lösung Vektoraddition
Dokument-Autor
... ... @@ -1,1 +1,1 @@
1 -XWiki.akukin
1 +XWiki.daniel2217
Inhalt
... ... @@ -1,14 +1,17 @@
1 -{{formula}}
2 -\begin{align*}\overrightarrow{AB} &= \left(\begin{array}{c} 5-3 \\ 2-1 \\ 4-5\end{array}\right) = \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right) \\
3 -\overrightarrow{CA} &= \left(\begin{array}{c} 3-8 \\ 1-7 \\ 5-1 \end{array}\right) = \left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) \\
4 -\overrightarrow{BC} &= \left(\begin{array}{c} 8-5 \\ 7-2 \\ 1-4 \end{array}\right) = \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) \\
1 +{{formula}}\begin{align*}\overrightarrow{AB} &= \left(\begin{array}{c} 5-3 \\ 2-1 \\ 4-5\end{array}\right) &= \left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right) \\
2 +\overrightarrow{CA} &= \left(\begin{array}{c} 3-8 \\ 1-7 \\ 5-1 \end{array}\right) &= \left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) \\
3 +\overrightarrow{BC} &= \left(\begin{array}{c} 8-5 \\ 7-2 \\ 1-4 \end{array}\right) &= \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) \\
5 5  \overrightarrow{DA} &= \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right)
6 6  \end{align*}
7 7  {{/formula}}
8 8  
9 -{{formula}}\overrightarrow{AB}-\overrightarrow{CA}+\overrightarrow{BC}-\overrightarrow{DA}=\overrightarrow{o}{{/formula}}
8 +{{formula}}
9 +\overrightarrow{AB}-\overrightarrow{CA}+\overrightarrow{BC}-\overrightarrow{DA}&=\overrightarrow{o}
10 +{{/formula}}
10 10  
11 -{{formula}}\left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right)-\left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) + \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) - \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right)= \left(\begin{array}{c} 0 \\ 0 \\ 0 \end{array}\right){{/formula}}
12 +{{formula}}
13 +\left(\begin{array}{c} 2 \\ 1 \\ -1\end{array}\right)-\left(\begin{array}{c} -5 \\ -6 \\ 4 \end{array}\right) + \left(\begin{array}{c} 3 \\ 5 \\ -3 \end{array}\right) - \left(\begin{array}{c} 3-d_1 \\ 1-d_2 \\ 5-d_3 \end{array}\right) &= \left(\begin{array}{c} 0 \\ 0 \\ 0 \end{array}\right)
14 +{{/formula}}
12 12  
13 13  {{formula}}
14 14  \begin{align*}