Wiki-Quellcode von Lösung Probeaufgabe
Version 1.1 von Daniel Stocker am 2023/11/30 14:27
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author | version | line-number | content |
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1.1 | 1 | {{formula}}3 + a_1 = 0,5{{/formula}} |
2 | |||
3 | {{formula}}\Rightarrow a_1 = -2,5{{/formula}} | ||
4 | |||
5 | {{formula}}\Rightarrow a_2 =2,5{{/formula}}, da ein Vektor der zweiten Winkelhalbierenden z.B. {{formula}}\left(\begin{array}{c} -1 \\ 1 \end{array}\right){{/formula}} ist | ||
6 | |||
7 | {{formula}}1 + a_2 = d{{/formula}} | ||
8 | |||
9 | {{formula}}1 + 2,5 = d{{/formula}} | ||
10 | |||
11 | {{formula}}d = 3,5{{/formula}} |