Wiki-Quellcode von Lösung Segelregatta
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| author | version | line-number | content |
|---|---|---|---|
| 1 | (%class=abc%) | ||
| 2 | 1. ((({{formula}}\overrightarrow{f_1}= 3 \vec{b}+\frac{5}{3} \vec{c} = \textcolor{green!50!black}{\left(\begin{array}{c} -30 \\ 80 \end{array}\right)}{{/formula}} | ||
| 3 | |||
| 4 | {{formula}}\overrightarrow{f_2}= \vec{a}-2 \vec{b}+\frac{7}{2} \vec{c} = \textcolor{green!50!black}{\left(\begin{array}{c} 45 \\ 95 \end{array}\right)}{{/formula}} | ||
| 5 | |||
| 6 | {{formula}}\overrightarrow{f_3}= \vec{a}- \vec{b}+\frac{3}{4} \vec{d} = \textcolor{green!50!black}{\left(\begin{array}{c} 95 \\ 0 \end{array}\right)}{{/formula}} | ||
| 7 | |||
| 8 | {{formula}}\overrightarrow{f_4}= 2\vec{b}-6,5\vec{c} = \textcolor{green!50!black}{\left(\begin{array}{c} -20 \\ -175 \end{array}\right)}{{/formula}} | ||
| 9 | |||
| 10 | [[image:segelregattateil2Lösung.jpg||width="600" style="display:block;margin-left:auto;margin-right:auto"]] | ||
| 11 | Die letzte Boje wird nicht von außen umsegelt, das Team wählt also einen kürzeren Weg als erlaubt. Der Kurs ist somit nicht regelkonform.))) | ||
| 12 | 1. ((({{formula}}|\overrightarrow{s_1}|=\sqrt{(-20)^2+80^2}=20\sqrt{17}\approx 82,46{{/formula}} | ||
| 13 | |||
| 14 | {{formula}}|\overrightarrow{s_2}|=\sqrt{20^2+50^2}=10\sqrt{29}\approx 53,85{{/formula}} | ||
| 15 | |||
| 16 | {{formula}}|\overrightarrow{s_3}|=\sqrt{75^2+40^2}=85{{/formula}} | ||
| 17 | |||
| 18 | {{formula}}|\overrightarrow{s_4}|=\sqrt{35^2+(-55)^2}=5\sqrt{170}\approx 65,19{{/formula}} | ||
| 19 | |||
| 20 | {{formula}}|\overrightarrow{s_5}|=\sqrt{(-20)^2+(-115)^2}=5\sqrt{545} \approx 116,73{{/formula}}))) | ||
| 21 | |||
| 22 | {{formula}}|\overrightarrow{s_1}|+|\overrightarrow{s_2}|+|\overrightarrow{s_3}|+|\overrightarrow{s_4}|+|\overrightarrow{s_5}|\approx 403,23{{/formula}} | ||
| 23 | |||
| 24 | Sie legen 403,23 km zurück. |