Lösung Bierfass

Version 1.1 von Daniel Stocker am 2024/02/06 10:06

\(\vec F = \left(\begin{array}{c} 0 \\ 0 \\ -98,1\end{array}\right) \)
\(S_R = ( 0 | 0 | 0) \)
Länge der Rampe = \(\sqrt{2^2+0,5^2} \approx 1,39\)
\(E_R = ( 0 | 1,39 | 0,5) \)
\(\vec s = \vec{S_RE_R} = \vec{OE_R}-\vec{OS_R} = \left(\begin{array}{c} 0 \\ 1,39 \\ 0,5\end{array}\right) \)