Wiki-Quellcode von Lösung Gezeitenkraftwerk
Version 1.6 von thomashermann am 2026/05/12 19:03
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| author | version | line-number | content |
|---|---|---|---|
 |
1.1 | 1 | (%class=abc%) |
| 2 | 1. Die Periodendauer beträgt {{formula}}p=12{{/formula}} Stunden. | ||
| |
1.3 | 3 | 1. Durch Kästchen zählen oder {{formula}}(8-2)\cdot 10= 60{{/formula}} Mio. Kubikmeter. |
| 4 | 1. Der Funktionsterm ist: {{formula}}f(t)=10 sin(\frac{\pi}{6}(t-2)){{/formula}}. | ||
| 5 | 1. Es gilt: | ||
| 6 | {{formula}} | ||
| 7 | \begin{eqnarray} | ||
| |
1.6 | 8 | \int^{8}_{2}10 sin(\frac{\pi}{6}(t-2)) dt &=& \Big[-10 cos(\frac{\pi}{6}(t-2))\frac{6}{\pi}\Big]^{8}_{2}\\ |
| 9 | &=& -10 cos(\frac{\pi}{6}(8-2))\frac{6}{\pi}+10 cos(\frac{\pi}{6}(2-2))\frac{6}{\pi} | ||
| |
1.3 | 10 | \end{eqnarray} |
| 11 | {{/formula}} |