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Lösung Fruchgummis

Version 15.1 von Stefan Martin am 2025/12/17 13:34

Die Wahrscheinlichkeit für das Ereignis E = "kein gelbes Fruchtgummi" lässt sich z. B. berechnen, in dem die Wahrscheinlichkeit des sog. Gegenereignisses ermittelt und diese schlussendlich von 1 subtrahiert wird:

\[\begin{aligned} P(E) & = 1-(P(\text{"gelb, gelb"}) + P(\text{"gelb, rot"}) + P(\text{"gelb, weiß"}) + P(\text{"gelb, grün"}) ) \\ & = 1- (313⋅212+2⋅313⋅712+2⋅313⋅212+2⋅313⋅112) \\ & = 1526 \\ \end{aligned}\]

Die Aussage ist also richtig. 

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