Wiki-Quellcode von Lösung Exponentialgleichungen lösen
Version 3.1 von Christoph Gommel am 2026/02/02 16:03
Verstecke letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
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3.1 | 1 | \begin{align*} |
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2.1 | 2 | a) {{formula}} 4\cdot 5^x+20=120 \quad \mid -20{{/formula}} |
| 3 | {{formula}} \quad 4\cdot 5^x=100 \quad \quad \mid :4{{/formula}} | ||
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1.1 | 4 | {{formula}} e^x=6 \quad \mid ln( ) {{/formula}} |
| 5 | {{formula}} x=ln(6) {{/formula}} | ||
| 6 | {{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}} | ||
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3.1 | 7 | \end{align*} |