Wiki-Quellcode von Lösung Exponentialgleichungen lösen
Version 7.1 von Christoph Gommel am 2026/02/02 16:46
Zeige letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
| 1 | |||
| 2 | a) | ||
| 3 | {{formula}} | ||
| 4 | \begin{align*} | ||
| 5 | 4\cdot 5^x+20=120 &&& \mid -20 \\ | ||
| 6 | 4\cdot 5^x=100 &&& \mid :4 \\ | ||
| 7 | 5^x=25 &&& \\ | ||
| 8 | 5^x=5^2 &&& \mid Koeffizientenvergleich \\ | ||
| 9 | x=2 \\ | ||
| 10 | \mathbb{L}= \left\{ 2 \right\} | ||
| 11 | \end{align*} | ||
| 12 | {{/formula}} | ||
| 13 | |||
| 14 | b) | ||
| 15 | {{formula}} | ||
| 16 | \begin{align*} | ||
| 17 | 2\cdot (2^x+4)=8 &&& \mid :2 \\ | ||
| 18 | 2^x+4=4 &&& \mid -4 \\ | ||
| 19 | 2^x=0 &&& \\ | ||
| 20 | \mathbb{L}= \left\{ \right\} | ||
| 21 | \end{align*} | ||
| 22 | {{/formula}} | ||
| 23 | |||
| 24 | c) | ||
| 25 | {{formula}} | ||
| 26 | \begin{align*} | ||
| 27 | 2\cdot 3^x=6 &&& \mid :2 \\ | ||
| 28 | 3^x=3 \\ | ||
| 29 | \mathbb{L}= \left\{ 1 \right\} | ||
| 30 | \end{align*} | ||
| 31 | {{/formula}} |