Änderungen von Dokument BPE 1.1 Rechnen mit Termen
Zuletzt geändert von Holger Engels am 2025/08/11 19:10
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... ... @@ -199,13 +199,24 @@ 199 199 (%class="border"%) 200 200 |Term |Auswahlmöglichkeiten |Lösungsfeld 201 201 |1) {{formula}}2x^2 + x^2{{/formula}} | a) {{formula}}3x^4{{/formula}} \\ b) {{formula}}2x^4{{/formula}} \\ c) {{formula}}3x^2{{/formula}} | 202 -|2) {{formula}}(-1)^2 + (5x)^0 + 3^0{{/formula}} | a) {{formula}}6x+4{{/formula}} \\ b) 1 \\ c) 3 | 202 +|2) {{formula}}(-1)^2 + (5x)^0 + 3^0{{/formula}} | a) {{formula}}6x+4{{/formula}} \\ b) {{formula}}1{{/formula}} \\ c) {{formula}}3{{/formula}} | 203 203 |3) {{formula}}3^{2x} \cdot 3^x{{/formula}} | a) {{formula}}3^{2x^2}{{/formula}} \\ b) {{formula}}3^{3x}{{/formula}} \\ c) {{formula}}9^{2x^2}{{/formula}} | 204 204 |4) {{formula}}(5b^2)^8{{/formula}} | a) {{formula}}5b^6{{/formula}} \\ b) {{formula}}125b^6{{/formula}} \\ c) {{formula}}125b^5{{/formula}} | 205 -|5) {{formula}}5 \cdot 3^x - 3^x{{/formula}} | a) {{formula}}4 \cdot 3^x{{/formula}} \\ b) {{formula}}12^x{{/formula}} \\ c) 5 | 205 +|5) {{formula}}5 \cdot 3^x - 3^x{{/formula}} | a) {{formula}}4 \cdot 3^x{{/formula}} \\ b) {{formula}}12^x{{/formula}} \\ c) {{formula}}5{{/formula}} | 206 206 |6) {{formula}}ab^2 : ab{{/formula}} | a) {{formula}}b^3{{/formula}} \\ b) {{formula}}b{{/formula}} \\ c) {{formula}}a^2b^2{{/formula}} | 207 207 |7) {{formula}}2x^2y + 3xy^2 + 5xy^2 - 7x^2y{{/formula}} | a) {{formula}}3x^2y^3{{/formula}} \\ b) {{formula}}8xy^2 - 5x^2y{{/formula}} \\ c) {{formula}}3x^2y^2{{/formula}} | 208 -|8) {{formula}}10^x : 10^x{{/formula}} | a) {{formula}}10^{2x}{{/formula}} \\ b) 1 \\ c) 10 | 208 +|8) {{formula}}10^x : 10^x{{/formula}} | a) {{formula}}10^{2x}{{/formula}} \\ b) {{formula}}1{{/formula}} \\ c) {{formula}}10{{/formula}} | 209 209 {{/aufgabe}} 210 210 211 +{{aufgabe id="Binome ergänzen" afb="II" quelle="Team Mathebrücke" kompetenzen="" zeit="" cc="by-sa" tags="mathebrücke"}} 212 +Trage jeweils ein, welche Werte für die Symbole eingesetzt werden müssen, so dass die Termumformung richtig ist. 213 +(%class="border"%) 214 +|Aufgabe |Lösung 215 +|a) {{formula}}(x + \square)(x - \square) = x^2 - 25{{/formula}} | {{formula}}\square={{/formula}} 216 +|b) {{formula}}(2x - \square)^2 = 4x^2 - \Delta + 9{{/formula}}| {{formula}}\square={{/formula}} {{formula}}\Delta={{/formula}} 217 +|c) {{formula}}(x - \square)^2 = x^2 - 4xy + \Delta{{/formula}}| {{formula}}\square={{/formula}} {{formula}}\Delta={{/formula}} 218 +|d) {{formula}}(2z - \square)^2 =\heartsuit -8z + \Delta{{/formula}} | {{formula}}\square={{/formula}} {{formula}}\Delta={{/formula}} 219 +|e) {{formula}}(4x - \square)(4x + \square) = \Delta - 49y^2{{/formula}} | {{formula}}\square={{/formula}} {{formula}}\Delta{{/formula}} {{formula}}\heartsuit{{/formula}} 220 +{{/aufgabe}} 221 + 211 211 {{seitenreflexion bildungsplan="" kompetenzen="" anforderungsbereiche="" kriterien="" menge=""/}}