Wiki-Quellcode von Lösung Rechenschritte
Version 4.1 von Martina Wagner am 2025/11/25 14:25
Zeige letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
| 1 | Azra hat Recht | ||
| 2 | |||
| 3 | {{formula}}\frac{1}{4x-3}=3 {{/formula}} | ||
| 4 | {{formula}} D = \{\frac{3}{4}\}{{/formula}} {{formula}}\quad{{/formula}} die Definitionsmenge muss lauten: | ||
| 5 | {{formula}} D = \mathbb{R} \backslash\{\frac{3}{4}\}{{/formula}}, da man für {{formula}} x=\frac{3}{4} {{/formula}}durch null teilen würde. | ||
| 6 | |||
| 7 | {{formula}} 1 = 12x - 9 {{/formula}} | ||
| 8 | Formt man die Gleichung um, wie Alex es gemacht hat ({{formula}} 1 = 12x - 9 {{/formula}} ), bleibt die Definitionsmenge der ursprünglichen Gleichung. | ||
| 9 | |||
| 10 | {{formula}} 1 = 12x - 9 {{/formula}} | ||
| 11 | {{formula}}12x = 10 {{/formula}} | ||
| 12 | {{formula}}x = \frac{10}{12}{{/formula}} | ||
| 13 | {{formula}} L = \{\frac{10}{12}\} {{/formula}} |