Lösung Normalparabel

Version 3.1 von slavko Lamp am 2025/10/01 11:51

x11,31,52,582270
y11,692,256,25644844900
x\(-\sqrt{3}\)\(\frac{1}{4}\)01,628\(\sqrt47{{{formula}}|0,9 |=y|3|{{formula}}\frac{1}{16}{{/formula}}|0|2,56|784|47|0,81\)