Änderungen von Dokument BPE 2 Einheitsübergreifend

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...	...	@@ -45,15 +45,16 @@
45	45	1. (((Seine dortigen Beispiele mögen hier der Übung des Darstellungswechsels dienen. Ermittle (falls möglich) aus der gegebenen Hauptform die //Produktform//. Folge in Vorgehen und Darstellung obigen Beispielen (dem konkreten und dem allgemeinen).
46	46	(% class="border slim" %)
47	47	|Nr. |Hauptform |Scheitelform |Produktform
48		-|1 |{{formula}}y = x^2 - 4x + 3{{/formula}} | |
49		-|2 | |{{formula}}y = (x - 1)^2 + 4{{/formula}} |
50		-|3 | | |{{formula}}y = (x + 2)(x + 2){{/formula}}
	48	+|1 |{{formula}}y = x^2 - 4x + 3{{/formula}} |{{formula}}y = (x - 2)^2 - 1{{/formula}} |{{formula}}y = (x - 1)(x - 3){{/formula}}
	49	+|2 | |{{formula}}y = (x - 1)^2 + 4{{/formula}} |{{formula}}y = (x - (1 + 2i))(x - (1 - 2i)){{/formula}}
	50	+|3 | |{{formula}}y = (x + 2)^2{{/formula}} |{{formula}}y = (x + 2)(x + 2){{/formula}}
51	51	|4 |{{formula}}y = 2x^2 - 8x + 6{{/formula}} |{{formula}}y = 2(x - 2)^2 - 2{{/formula}} |{{formula}}y = 2(x - 1)(x - 3){{/formula}}
52		-|5 | |{{formula}}y = (x + 3)^2 - 9{{/formula}} |
53		-|6 | | |{{formula}}y = (x - 4)(x - 2){{/formula}}
54		-|7 |{{formula}}y = x^2 + 2x + 5{{/formula}} | |
55		-|8 | |{{formula}}y = (x - 2)^2{{/formula}} |
56		-|9 | | |{{formula}}y = (x - 2)(x - 3){{/formula}}
	52	+|5 | |{{formula}}y = (x + 3)^2 - 9{{/formula}} |{{formula}}y = (x + 6)(x){{/formula}}
	53	+|6 | |{{formula}}y = (x - 3)^2 - 1{{/formula}} |{{formula}}y = (x - 4)(x - 2){{/formula}}
	54	+|7 |{{formula}}y = x^2 + 2x + 5{{/formula}} |{{formula}}y = (x + 1)^2 + 4{{/formula}} |{{formula}}y = (x + (1 + 2i))(x + (1 - 2i)){{/formula}}
	55	+|8 | |{{formula}}y = (x - 2)^2{{/formula}} |{{formula}}y = (x - 2)(x - 2){{/formula}}
	56	+|9 |{{formula}}y = x^2 - 5x + 6{{/formula}} |{{formula}}y = (x - \frac{5}{2})^2 - \frac{1}{4}{{/formula}} |{{formula}}y = (x - 2)(x - 3){{/formula}}
	57	+
57	57
58	58	)))
59	59	1. (((Begründe, dass gilt: