Wiki-Quellcode von Lösung Basiswechel
Version 1.1 von Niklas Wunder am 2024/12/18 14:25
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| author | version | line-number | content |
|---|---|---|---|
 |
1.1 | 1 | a) {{formula}}(\frac{1}{4})^x=(2^{-x})^x=2^{-2x}{{/formula}} |
| 2 | b) {{formula}}(\frac{3}{18})^x=(\frac{1}{6})^=6^{-x}{{/formula}} | ||
| 3 | c) {{formula}}5^{2x+1}=5\cdot (5^2)^x=5\cdot 25^x{{/formula}} | ||
| 4 | d) {{formula}}(\frac{16}{54})^{2x}=(\frac{8}{27})^{2x}=(\frac{2}{3})^{3\cdot 2x}=(-\frac{2}{3})^{-6x}{{/formula}} |