Änderungen von Dokument Lösung Exponentialgleichungen (Logarithmieren)
Zuletzt geändert von Kim Fujan am 2025/05/20 11:11
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... ... @@ -3,26 +3,22 @@ 3 3 {{formula}} ln(e^x)=ln(3) {{/formula}} 4 4 {{formula}} x=ln(3) {{/formula}} 5 5 {{formula}}\mathbb{L}= \left\{ ln(3) \right\} {{/formula}} 6 - 7 - 8 8 1. {{formula}} 2e^x-4=8 \quad \left|+4{{/formula}} 9 9 {{formula}} 2e^x=12 \quad \left|:2{{/formula}} 10 10 {{formula}} e^x=6 \quad \left| ln( ) {{/formula}} 11 11 {{formula}} x=ln(6) {{/formula}} 12 12 {{formula}}\mathbb{L}= \left\{ ln(6) \right\} {{/formula}} 13 - 14 14 1. {{formula}} 2e^{-0.5x}=6 \quad \left|:2 {{/formula}} 15 15 {{formula}} e^{-0.5x}=3 \quad \left| ln( ) {{/formula}} 16 16 {{formula}} -0.5x=ln(3) \quad \left|\cdot (-2) {{/formula}} 17 17 {{formula}} x=-2 \cdot ln(3) {{/formula}} 18 18 {{formula}}\mathbb{L}= \left\{-2 \cdot ln(3) \right\} {{/formula}} 19 - 20 20 1. {{formula}} e^x=-5 \quad \left| ln( ) {{/formula}} 21 21 {{formula}}x=ln(-5){{/formula}} 22 22 keine Lösung! 23 23 {{formula}}\mathbb{L}= \left\{ \right\} {{/formula}} 24 - 25 25 1. {{formula}} 4\cdot 5^x=100 \quad \left|:4 {{/formula}} 26 26 {{formula}} 5^x=25 \quad \left| \text{Exponentenvergleich} {{/formula}} 27 27 {{formula}} 5^x=5^2 {{/formula}} 28 -{{formula}} x=5 {{/formula}} 23 +{{formula}} x=2 {{/formula}} 24 +{{formula}}\mathbb{L}= \left\{ 2 \right\} {{/formula}}