Wiki-Quellcode von Entwurf
Zuletzt geändert von Torben Würth am 2024/02/06 16:41
Verstecke letzte Bearbeiter
author | version | line-number | content |
---|---|---|---|
![]() |
1.1 | 1 | == Vektoren == |
2 | |||
![]() |
4.1 | 3 | {{aufgabe id="Vektoraddition zeichnerisch" afb="I" kompetenzen="K5" quelle="Torben Würth" cc="BY-SA" zeit="6"}} |
![]() |
5.1 | 4 | Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch {{formula}}\vec{a}+\vec{b}{{/formula}} |
![]() |
2.1 | 5 | a) |
![]() |
1.2 | 6 | {{formula}}\vec{a}= \left(\begin{array}{c}1\\3 \end{array}\right){{/formula}} ; {{formula}}\vec{b}= \left(\begin{array}{c}2\\4 \end{array}\right){{/formula}} |
![]() |
2.1 | 7 | b) |
8 | {{formula}}\vec{a}= \left(\begin{array}{c}-1\\2 \end{array}\right){{/formula}} ; {{formula}}\vec{b}= \left(\begin{array}{c}3\\-4 \end{array}\right){{/formula}} | ||
![]() |
1.1 | 9 | {{/aufgabe}} |
![]() |
4.1 | 10 | |
![]() |
6.1 | 11 | {{aufgabe id="Vektoraddition zeichnerisch 2" afb="I" kompetenzen="K5" quelle="Torben Würth" cc="BY-SA" zeit="8"}} |
![]() |
5.1 | 12 | Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch {{formula}}\vec{a}+\vec{b}+\vec{c}{{/formula}} |
![]() |
4.1 | 13 | a) |
14 | {{formula}}\vec{a}= \left(\begin{array}{c}2\\3 \end{array}\right){{/formula}} ; {{formula}}\vec{b}= \left(\begin{array}{c}4\\1 \end{array}\right){{/formula}} ; {{formula}}\vec{c}= \left(\begin{array}{c}-1\\2 \end{array}\right){{/formula}} | ||
15 | b) | ||
16 | {{formula}}\vec{a}= \left(\begin{array}{c}-2\\2 \end{array}\right){{/formula}} ; {{formula}}\vec{b}= \left(\begin{array}{c}3\\-4 \end{array}\right){{/formula}} {{formula}}\vec{c}= \left(\begin{array}{c}3\\3\end{array}\right){{/formula}} | ||
17 | {{/aufgabe}} | ||
![]() |
7.1 | 18 | |
19 | {{aufgabe id="Vektoraddition rechnerisch" afb="I" kompetenzen="K5" quelle="Torben Würth" cc="BY-SA" zeit="6"}} | ||
20 | Berechne | ||
21 | a) | ||
![]() |
7.2 | 22 | {{formula}}\left(\begin{array}{c}12\\7 \end{array}\right)+\left(\begin{array}{c}2\\4 \end{array}\right)={{/formula}} |
![]() |
7.1 | 23 | b) |
![]() |
7.3 | 24 | {{formula}}\left(\begin{array}{c}-16\\33 \end{array}\right)+\left(\begin{array}{c}0,5\\-33 \end{array}\right)={{/formula}} |
![]() |
8.3 | 25 | c) |
![]() |
8.2 | 26 | {{formula}}\left(\begin{array}{c}-1,5\\\frac{1}{3} \end{array}\right)+\left(\begin{array}{c}\sqrt{2}\\\pi\end{array}\right)={{/formula}} |
![]() |
8.3 | 27 | d) |
28 | {{formula}}\left(\begin{array}{c}\frac{1}{2}\sqrt{2}\\5\pi \end{array}\right)-\left(\begin{array}{c}\sqrt{2}\\\pi\end{array}\right)={{/formula}} | ||
![]() |
8.4 | 29 | e) |
![]() |
9.2 | 30 | {{formula}}\left(\begin{array}{c}\frac{3}{7}\\5 \end{array}\right)+\left(\begin{array}{c}\frac{5}{7}\\5 \end{array}\right)-\left(\begin{array}{c}\frac{1}{7}\\5 \end{array}\right)={{/formula}} |
![]() |
8.3 | 31 | |
![]() |
8.4 | 32 | f) |
![]() |
8.3 | 33 | {{formula}}\left(\begin{array}{c}1\\7\\9 \end{array}\right)+\left(\begin{array}{c}2\\4\\-1 \end{array}\right)={{/formula}} |
![]() |
8.4 | 34 | g) |
35 | {{formula}}\left(\begin{array}{c}100\\71\\92 \end{array}\right)+\left(\begin{array}{c}203\\4\\-119\end{array}\right)={{/formula}} | ||
36 | h) | ||
![]() |
8.5 | 37 | {{formula}}\left(\begin{array}{c}12,6\\8,1\\0,3\end{array}\right)-\left(\begin{array}{c}-0,6\\0,9\\\frac{1}{3}\end{array}\right)={{/formula}} |
![]() |
8.6 | 38 | i) |
39 | {{formula}}\left(\begin{array}{c}1\\0,5\\4\end{array}\right)-\left(\begin{array}{c}-1\\0,5\\4\end{array}\right)+\left(\begin{array}{c}-1\\-2\\20\end{array}\right)={{/formula}} | ||
![]() |
7.1 | 40 | {{/aufgabe}} |
![]() |
9.3 | 41 | |
42 | {{aufgabe id="Multiplikation eines Vektors mit einer Zahl zeichnerisch" afb="I" kompetenzen="K5" quelle="Torben Würth" cc="BY-SA" zeit="6"}} | ||
43 | a) Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch {{formula}}\vec{a}+\vec{a}=2\vec{a}{{/formula}} mit {{formula}}\vec{a}= \left(\begin{array}{c}1\\3 \end{array}\right){{/formula}} | ||
44 | b) Zeichne ein zweidimensionales Koordinatensystem und ermittle zeichnerisch {{formula}}\vec{a}+\vec{a}+\vec{a}=3\vec{a}{{/formula}} mit {{formula}}\vec{a}= \left(\begin{array}{c}-2\\1 \end{array}\right){{/formula}} | ||
45 | {{/aufgabe}} | ||
![]() |
9.4 | 46 | |
![]() |
9.7 | 47 | {{aufgabe id="Gemischte Aufgaben" afb="I" kompetenzen="K5" quelle="Torben Würth" cc="BY-SA" zeit="6"}} |
48 | a) {{formula}}2\left(\begin{array}{c}1\\3 \end{array}\right)={{/formula}} | ||
![]() |
9.4 | 49 | b) {{formula}}3\left(\begin{array}{c}-2\\1 \end{array}\right)={{/formula}} |
50 | c) {{formula}}6\left(\begin{array}{c}-1\\6 \end{array}\right)={{/formula}} | ||
51 | d) {{formula}}\frac{1}{3}\left(\begin{array}{c}-3\\18 \end{array}\right)={{/formula}} | ||
![]() |
9.5 | 52 | e) {{formula}}2\left(\begin{array}{c}\frac{3}{7}\\5 \end{array}\right)+ 3\left(\begin{array}{c}\frac{5}{7}\\5 \end{array}\right)-4\left(\begin{array}{c}\frac{1}{7}\\5 \end{array}\right)={{/formula}} |
![]() |
9.7 | 53 | f){{formula}}-2\left(\begin{array}{c}1\\0,5\\4\end{array}\right)-4\left(\begin{array}{c}-1\\0,5\\4\end{array}\right)+\frac{1}{2}\left(\begin{array}{c}-1\\-2\\20\end{array}\right)={{/formula}} |
54 | {{/aufgabe}} |