Wiki-Quellcode von Lösung Orthogonalen Vektor finden
Version 2.1 von Daniel Stocker am 2024/02/05 17:18
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| author | version | line-number | content |
|---|---|---|---|
| 1 | {{formula}}\vec u \cdot \vec v = \left(\begin{array}{c} 4 \\ 5 \\ 2\end{array}\right) \cdot \left(\begin{array}{c} \frac{2}{3} \\ a \\ 1\end{array}\right) = 4 \cdot \frac{2}{3} + 5 \cdot a + 2 \cdot (-1) \overset{!}{=} 0 {{/formula}} | ||
| 2 | |||
| 3 | {{formula}} | ||
| 4 | \begin{align*} | ||
| 5 | 4 \cdot \frac{2}{3} + 5 \cdot a + 2 \cdot (-1) &= 0 \\ | ||
| 6 | \frac{8}{3} + 5a -2 &= 0 \\ | ||
| 7 | \end{align*} | ||
| 8 | {{/formula}} |