Wiki-Quellcode von Lösung Entscheiden für den effektiven Lösungsweg
Zuletzt geändert von akukin am 2025/07/11 14:07
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1.1 | 1 | (%class=abc%) |
2 | 1. | ||
3 | (%class=border%) | ||
4 | |||abc-Formel \\bzw. \\pq-Formel |Ausklammern\\und Satz vom\\Nullprodukt|{{formula}}x^2{{/formula}} isolieren\\und Wurzel\\ziehen | ||
5 | |a)|{{formula}}x^2 + 2x - 3 = 0{{/formula}}|(%style="text-align:center;"%)x|| | ||
6 | |b)|{{formula}}4x^2 - 3 = 5{{/formula}}|||(%style="text-align:center;"%)x | ||
7 | |c)|{{formula}}2x^2 - x = 0{{/formula}}||(%style="text-align:center;"%)x| | ||
8 | |d)|{{formula}}5x - 14 = -x^2{{/formula}}|(%style="text-align:center;"%)x|| | ||
9 | |e)|{{formula}}4x^2 = x^2{{/formula}}|||(%style="text-align:center;"%)x | ||
10 | |f)|{{formula}}2x - 8x^2 = -3{{/formula}}|(%style="text-align:center;"%)x|| | ||
11 | |g)|{{formula}}4x(x - 3) = 0{{/formula}}||(%style="text-align:center;"%)x| | ||
12 | |h)|{{formula}}(x - 3)4x = 7{{/formula}}|(%style="text-align:center;"%)x|| | ||
13 | (%class=abc start="2" %) | ||
14 | 1. | ||
15 | (%class=noborder%) | ||
16 | |a) {{formula}}\text{L}=\{-3; 1\}{{/formula}}|b) {{formula}}\text{L}=\{-\sqrt{2}; \sqrt{2}\}{{/formula}}|c) {{formula}}\text{L}=\{0; 0,5\}{{/formula}} | ||
17 | |d) {{formula}}\text{L}=\{-7; 2\}{{/formula}}|e) {{formula}}\text{L}=\{0\}{{/formula}}|f) {{formula}}\text{L}=\{-0,5; 0,75\}{{/formula}} | ||
18 | |g) {{formula}}\text{L}=\{0; 3\}{{/formula}}|h){{formula}}\text{L}=\{-0,5; 3,5\}{{/formula}}| | ||
19 |