Änderungen von Dokument BPE 4.1 Exponentialfunktion und Eulersche Zahl
Zuletzt geändert von Holger Engels am 2025/03/11 21:51
Von Version 66.5
bearbeitet von Holger Engels
am 2025/02/25 12:28
am 2025/02/25 12:28
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Auf Version 69.1
bearbeitet von Holger Engels
am 2025/02/25 15:53
am 2025/02/25 15:53
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... ... @@ -9,13 +9,18 @@ 9 9 {{lehrende}} 10 10 x im Exponenten 11 11 * Welches ist eine Exponentialfunktion, welches nicht? Ordne zu ... (komplexere Terme mit/ ohne x im Exponenten) 12 + 12 12 Asymptotischer Verlauf 13 -* Schaubilder von tan(x), 1/100 x^2 und x^-2 .. jeweils Ausschnitte 14 -* 2^x und 2^-x = ½^x 14 +* Schaubilder , die durch (0|1) verlaufen 15 +* 1, 1 + 2x, 1 + x^2, 2^x, 1/2^x .. 1/x^2 für x<0 weiterzeichnen 16 +* Funktionswert an den Stellen -1, 0, 1, 2 17 + 15 15 Warum kommen nur positive Basen in Frage? 16 16 * Wertetabelle (-2)^x 17 -Basiswechsel (setzt ln voraus) 18 -* Potenzgesetz 20 + 21 +Basiswechsel 22 +* ohne ln 23 +* Auf Potenzgesetz zurückführen 19 19 {{/lehrende}} 20 20 21 21 {{lernende}} ... ... @@ -22,6 +22,20 @@ 22 22 [[GeoGebra-Buch>>https://www.geogebra.org/m/khnsgz5a#material/UcgSUN2M]] 23 23 {{/lernende}} 24 24 30 +{{aufgabe id="Exponentialfunktion" afb="I" kompetenzen="K5" quelle="Holger Engels" zeit="2"}} 31 +Entscheide jeweils, ob es sich bei dem Funktionsterm um einen Exponentialfunktionsterm handelt. 32 +(% class="abc" %) 33 +1. {{formula}}f(x) = \frac{1}{8}(2(x-2))^3 + e{{/formula}} 34 +1. {{formula}}f(x) = \frac{1}{8}x^{3(x+1)}-1{{/formula}} 35 +{{/aufgabe}} 36 + 37 +{{aufgabe id="Graphen" afb="I" kompetenzen="K4" quelle="Holger Engels" zeit="8"}} 38 +Ordne die Funktionsgraphen den Funktionstermen zu und skizziere jeweils im Schaubild den Abschnitt für //x<0//. 39 +{{formula}}f(x)=1+2x{{/formula}} {{formula}}g(x)=1 + x^2{{/formula}} {{formula}}h(x)=(\frac{1}{2})^x{{/formula}} {{formula}}\frac{1}{(x+1)^2}{{/formula}}{{formula}}i(x)=2^x{{/formula}} 40 +[[image:graph f.svg||style="margin: 8px"]] [[image:graph g.svg||style="margin: 8px"]] [[image:graph h.svg||style="margin: 8px"]] [[image:graph p.svg||style="margin: 8px"]] [[image:graph q.svg||style="margin: 8px"]] [[image:graph r.svg||style="margin: 8px"]] 41 +(% class="abc" %) 42 +{{/aufgabe}} 43 + 25 25 {{aufgabe id="Basiswechel" afb="I" kompetenzen="K4" quelle="Niklas Wunder, Katharina Schneider" zeit="10"}} 26 26 Wandle die gegeben Exponentialfunktion in die entsprechende Basis um, z.B. {{formula}}f(x)=(\frac{1}{2})^x= 2^{-x}{{/formula}} ist eine Umwandlung in die neue Basis {{formula}}b=2{{/formula}} 27 27 {{formula}}f(x)=(\frac{1}{4})^x{{/formula}} in die neue Basis {{formula}}b=2{{/formula}} ... ... @@ -36,8 +36,6 @@ 36 36 Bestimme zu jedem Schaubild eine passende Funktionsgleichung. 37 37 38 38 [[image:Exponentialfunktionen.svg||width=600]] 39 - 40 - 41 41 {{/aufgabe}} 42 42 43 43 {{aufgabe id="e-Funktion im Vergleich" afb="II" kompetenzen="K4" quelle="Niklas Wunder, Katharina Schneider" zeit="5"}} ... ... @@ -44,7 +44,6 @@ 44 44 Gegeben ist der Graph zu {{formula}}f(x)=e^x{{/formula}}. Skizziere deine Vermutung wie die Graphen von {{formula}}g(x)=2^x{{/formula}} und {{formula}}h(x)=3^x{{/formula}} verlaufen. 45 45 (Ohne Taschenrechner, ohne Wertetabelle) 46 46 [[image:EFunktion.svg||width=500]] 47 - 48 48 {{/aufgabe}} 49 49 50 50 {{aufgabe id="Eigenschaften der e-Funktion" afb="I" kompetenzen="K4" quelle="Niklas Wunder, Katharina Schneider" zeit="5"}} ... ... @@ -60,7 +60,6 @@ 60 60 a) Welchem Muster lässt sich bei der Berechnung erkennen? Führe das Muster fort und berechne {{formula}} a_5, a_6 61 61 {{/formula}}. 62 62 b) Die eulersche Zahl {{formula}} e{{/formula}} ist gegben durch {{formula}} e= 2+\frac{1}{1\cdot 2}+\frac{1}{1\cdot 2\cdot 3}+\frac{1}{1\cdot 2\cdot 3\cdot 4}+ ...{{/formula}}, d.h durch Fortsetzung des Musters berechnet man die Zahl {{formula}} e{{/formula}} auf immer mehr Nachkommastellen. Gib die Zahl {{formula}} e{{/formula}} so genau an, wie du sie in a) berechnet hast. Hinweis: Du kannst gerne noch mehr weiter Zahlterme {{formula}} a_7,a_8, usw.{{/formula}}, wenn du eine noch höhere Genauigheit haben willst. 63 - 64 64 {{/aufgabe}} 65 65 66 66 {{lehrende}}
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