Änderungen von Dokument BPE 4.5 Logarithmus und Exponentialgleichungen

Zusammenfassung

• Seiteneigenschaften (2 geändert, 0 hinzugefügt, 0 gelöscht)

Details

Seiteneigenschaften

Dokument-Autor

...	...	@@ -1,1 +1,1 @@
1		-XWiki.martinawagner
	1	+XWiki.fujan

Inhalt

...	...	@@ -32,10 +32,10 @@
32	32	{{aufgabe id="Exponentialgleichungen (Substitution)" afb="I" kompetenzen="K5" quelle="Martin Rathgeb" cc="BY-SA" zeit="12"}}
33	33	Bestimme die Lösungsmenge der Gleichung:
34	34	(% class="abc" %)
35		-1. {{formula}} -x^{2}+2x-3=0 {{/formula}}
36		-1. {{formula}} -e^{2x}+2e^x-3=0 {{/formula}}
37		-1. {{formula}} e^x+2e^{\frac{1}{2}x}-3=0 {{/formula}}
38		-1. {{formula}} e^x-2-\frac{15}{e^x}}=0 {{/formula}}
	35	+1. {{formula}} x^{2}-2x-3=0 {{/formula}}
	36	+1. {{formula}} e^{2x}-2e^x-3=0 {{/formula}}
	37	+1. {{formula}} e^x-2e^{\frac{1}{2}x}-3=0 {{/formula}}
	38	+1. {{formula}} e^x-2-\frac{8}{e^x}}=0 {{/formula}}
39	39	1. {{formula}} 2e^{4x}=e^{2x}+3 {{/formula}}
40	40	{{/aufgabe}}
41	41
...	...	@@ -86,7 +86,7 @@
86	86	|{{formula}} 2^{-x} = 8 {{/formula}}|{{formula}} x = \log_{2}(8) {{/formula}} |(((
87	87	|x|0|1|2|3
88	88	|y|1|{{formula}}\frac{1}{2}{{/formula}}|{{formula}}\frac{1}{4}{{/formula}}|{{formula}}\frac{1}{8}{{/formula}}
89		-)))|[[image:x^3und8.svg||width="200px"]]
	89	+)))|[[image:x^-3und8.svg||width="200px"]]
90	90	{{/aufgabe}}
91	91
92	92	{{aufgabe id="Gleichungen gemeinsamer Form" afb="III" kompetenzen="K5" quelle="Martin Rathgeb" cc="BY-SA" zeit="6"}}
...	...	@@ -264,12 +264,13 @@
264	264	{{formula}}
265	265	\begin{align*}
266	266	e^{2x}-\square e^x &= 0 \\
267		-e^x(\square-\square) &= 0 \left|\left| \text{ SVNP }
	267	+e^x \cdot (\square-\square) &= 0 \left|\left| \text{ SVNP }
268	268	\end{align*}
269	269	{{/formula}}
270	270
271		-{{formula}}\ e^x \neq 0 ~und~ e^x-\square = 0{{/formula}}
272		-
	271	+{{formula}}
	272	+e^x \neq 0 ~und~ e^x-\square = 0{{/formula}}
	273	+{{formula}} e^x=\square {{/formula}}
273	273	{{formula}} x =\square {{/formula}}
274	274	)))
275	275	1. ((({{{ }}}