Wiki-Quellcode von Lösung Vektoren Sechseck
Version 6.1 von Frauke Beckstette am 2024/02/06 10:11
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author | version | line-number | content |
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1 | 1. Es gilt {{formula}}\Vec{x}= \overrightarrow{BE}{{/formula}} und {{formula}}\Vec{y}= \overrightarrow{FE}{{/formula}}. | ||
2 | 1. {{formula}}\overrightarrow{FB}=\Vec{f}-\Vec{e}-\Vec{c}{{/formula}} | ||
3 | 1. Es gilt {{formula}}\overrightarrow{OB}=\overrightarrow{OA}+ 4 \cdot \overrightarrow{AK}= \left(\begin{array}{c} 6 \\ 2 \\ -4 \end{array}\right) + 4 \cdot \left(\begin{array}{c} 2-6 \\ 0-2 \\ 8-(-4) \end{array}\right)= \left(\begin{array}{c} 6 + 4\cdot (-4) \\ 2+ 4 \cdot (-2) \\ -4 + 4 \cdot 12 \end{array}\right)=\left(\begin{array}{c} -10 \\ -6 \\ 44 \end{array}\right){{/formula}} | ||
4 | Somit lautet der Punkt {{formula}}B(-10|-6|44){{/formula}}. |