Lösung Bierfass

Version 1.2 von Daniel Stocker am 2024/02/06 11:08

$\vec F = \left(\begin{array}{c} 0 \\ 0 \\ -98,1\end{array}\right)$
S_R = ( 0 | 0 | 0)
Länge der Rampe = $\sqrt{2^2+0,5^2} \approx 1,39$
E_R = ( 0 | 1,39 | 0,5)
$\vec s = \overrightarrow{S_RE_R} = \overrightarrow{OE_R}-\overrightarrow{OS_R} = \left(\begin{array}{c} 0-0 \\ 1,39-0 \\ 0,5-0\end{array}\right) = \left(\begin{array}{c} 0 \\ 1,39 \\ 0,5\end{array}\right)$